Import Question JSON

Current Question (ID: 8691)

Question:
$\text{The incorrect statement among the following regarding }\text{H}_2\text{O}_2\text{ is -}$
Options:
  • 1. $\text{It can only act as an oxidising agent}$
  • 2. $\text{It decomposes on exposure to light}$
  • 3. $\text{It has to be stored in plastic or wax-lined glass bottles in dark}$
  • 4. $\text{It has to be kept away from dust}$
Solution:
\text{Hint: } \text{H}_2\text{O}_2 \text{ can act both as a reductant and an oxidant.} \text{a. } \text{H}_2\text{O}_2 \text{ can behave both as an oxidising agent and a reducing agent. The reactions are:} 2\text{Fe}^{2+} + 2\text{H}^{+} + \text{H}_2\text{O}_2 \rightarrow 2\text{Fe}^{3+} + 2\text{H}_2\text{O} \text{I}_2 + \text{H}_2\text{O}_2 + 2\text{OH}^{-} \rightarrow 2\text{I}^{-} + 2\text{H}_2\text{O} + \text{O}_2 \text{b. } \text{H}_2\text{O}_2 \text{ decomposes slowly on exposure to light:} 2\text{H}_2\text{O}_2 \rightarrow 2\text{H}_2\text{O} + \text{O}_2 \text{c. In the presence of metal surfaces or traces of alkali, } \text{H}_2\text{O}_2 \text{ decomposition is catalysed.} \text{It is stored in wax-lined glass or plastic vessels in dark conditions.} \text{d. It is kept away from dust because dust can induce explosive decomposition.}

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}