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Current Question (ID: 8694)

Question:
$\text{H}_2\text{O}_2 \text{ act as a reducing agent in:}$
Options:
  • 1. $\text{Reaction with a ferrous salt.}$
  • 2. $\text{Reaction with iodides.}$
  • 3. $\text{Reaction with lead sulphide.}$
  • 4. $\text{Reaction with } \text{KMnO}_4 \text{ in an acid medium.}$
Solution:
$\text{Hint: When } \text{H}_2\text{O}_2 \text{ acts as a reducing agent it convert into } \text{O}_2\text{.}$ $\text{Hydrogen peroxide acts as both a reducing and an oxidizing agent.}$ $\text{When } \text{H}_2\text{O}_2 \text{ serves as an oxidizing agent, the oxygen of hydrogen peroxide (that is present in -1 oxidation state) is reduced to } \text{H}_2\text{O} \text{ (-2 oxidation state).}$ $\text{H}_2\text{O}_2 + 2\text{H}^+ + 2\text{e}^- \rightarrow 2\text{H}_2\text{O}$ $\text{When } \text{H}_2\text{O}_2 \text{ (-1 oxidation state) serves as a reducing agent, the oxygen of } \text{H}_2\text{O}_2 \text{ is oxidized to } \text{O}_2 \text{ (0 oxidation state) and bubbles are noticed. As a reducing agent:}$ $2\text{KMnO}_4 + 5\text{H}_2\text{O}_2 + 3\text{H}_2\text{SO}_4 \rightarrow \text{K}_2\text{SO}_4 + 5\text{O}_2 + 2\text{MnSO}_4 + 8\text{H}_2\text{O}$ $\text{The reactions of } \text{H}_2\text{O}_2 \text{ with other substances given in other options are as follows:}$ $\text{The reaction with lead sulphide is as follows:}$ $\text{PbS} + 4\text{H}_2\text{O}_2 \rightarrow \text{PbSO}_4 + 4\text{H}_2\text{O}$ $\text{The reaction with iodide is as follows:}$ $2\text{I}^- + \text{H}_2\text{O}_2 + 2\text{H}^+ \rightarrow \text{I}_2 + 2\text{H}_2\text{O}$ $\text{The reaction with ferrous salt is as follows:}$ $2\text{Fe}^{2+} + \text{H}_2\text{O}_2 + 2\text{H}^+ \rightarrow 2\text{Fe}^{3+} + 2\text{H}_2\text{O}$ $\text{In the reaction with } \text{KMnO}_4\text{, } \text{H}_2\text{O}_2 \text{ is oxidized to } \text{O}_2\text{, making it act as a reducing agent. In the other reactions, } \text{H}_2\text{O}_2 \text{ is reduced to } \text{H}_2\text{O}\text{, making it act as an oxidizing agent.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}