Import Question JSON

Current Question (ID: 8696)

Question:

$\text{H}_2\text{O}_2 \text{ is prepared in the laboratory by the reaction of:}$

Options:

1. $\text{MnO}_2 \text{ with dilute cold } \text{H}_2\text{SO}_4$
2. $\text{BaO}_2 \text{ and } \text{CO}_2 \text{ bubbling through cold water}$
3. $\text{PbO}_2 \text{ with an acidified solution of } \text{KMnO}_4$
4. $\text{Na}_2\text{O}_2 \text{ with boiling water}$

Solution:

$\text{Hint: Barium peroxide reacts with } \text{CO}_2\text{.}$ $\text{In lab } \text{H}_2\text{O}_2 \text{ is prepared by reaction of } \text{BaO}_2 \cdot \text{8H}_2\text{O} \text{ and } \text{H}_2\text{SO}_4\text{(cold). A paste of } \text{BaO}_2 \cdot \text{8H}_2\text{O} \text{ is prepared in ice-cold water and then added gradually to ice-cold dilute sulphuric acid.}$ $\text{The reaction is as follows:}$ $\text{BaO}_2 + \text{CO}_2 + \text{H}_2\text{O} \rightarrow \text{H}_2\text{O}_2 + \text{BaCO}_3$ $\text{This reaction shows that barium peroxide } (\text{BaO}_2) \text{ reacts with carbon dioxide } (\text{CO}_2) \text{ in the presence of water to produce hydrogen peroxide } (\text{H}_2\text{O}_2) \text{ and barium carbonate } (\text{BaCO}_3)\text{.}$ $\text{Other reactions mentioned include:}$ $2\text{Na}_2\text{O}_2 + 2\text{H}_2\text{O}_{(l)} \rightarrow 4\text{NaOH} + \text{O}_2_{(g)}$ $\text{Therefore, the correct answer is option 2: } \text{BaO}_2 \text{ and } \text{CO}_2 \text{ bubbling through cold water.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}