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Current Question (ID: 8701)

Question:

$\text{The following reaction is an example of:}$ $2\text{MnO}_4^- + 6\text{H}^+ + 5\text{H}_2\text{O}_2 \rightarrow 2\text{Mn}^{2+} + 8\text{H}_2\text{O} + 5\text{O}_2$

Options:

1. $\text{Hydrolysis reaction}$
2. $\text{Redox reaction}$
3. $\text{Disproportionation reaction}$
4. $\text{None of the above}$

Solution:

$\text{HINT: Oxidation and reduction both occur simultaneously}$ $\text{Explanation:}$ $\text{STEP 1:}$ $\text{A redox reaction can be defined as a chemical reaction in which electrons are transferred between two reactants participating in it.}$ $\text{STEP 2:}$ $\text{In the reaction: } 2\text{MnO}_4^-_{(\text{aq})} + 5\text{H}_2\text{O}_{2(\text{aq})} \rightarrow 6\text{H}^+_{(\text{aq})} + 2\text{Mn}^{2+}_{(\text{aq})} + 8\text{H}_2\text{O}_{(\text{l})} + 5\text{O}_{2(\text{g})}$ $\text{The oxidation state of Mn is changing from +7 to +2. Also, H}_2\text{O}_2 \text{ is getting oxidized. The oxidation state of oxygen is -1 in H}_2\text{O}_2$ $\text{and the oxidation state of oxygen in O}_2 \text{ is zero. Hence, oxidation takes place.}$ $\text{Thus, H}_2\text{O}_{2(\text{aq})} \text{ acts as a reducing agent in the acidic medium, thereby reducing MnO}_4^-_{(\text{aq})}\text{. Hence, the given reaction is a redox reaction.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}