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Current Question (ID: 8707)

Question:

$\text{10 volumes of H}_2\text{O}_2 \text{ has a strength of approximately:}$

Options:

1. $3\%$
2. $30\%$
3. $10\%$
4. $5\%$

Solution:

$\text{Hint: 10 volumes of H}_2\text{O}_2 \text{ means 10 litres of oxygen is obtained at STP by the decomposition of 1 litre H}_2\text{O}_2 \text{ solution}$ $\text{Percent concentration of H}_2\text{O}_2 = \frac{17}{56} \times \text{volume conc. of H}_2\text{O}_2$ $= \frac{17}{56} \times 10$ $= 3\% \text{ app.}$ $\text{Or}$ $\text{There is another method which is shown below:}$ $2\text{H}_2\text{O}_2\text{(l)} \rightarrow \text{O}_2\text{(g)} + \text{H}_2\text{O}\text{(l)}$ $2 \times 34 \text{ g} \rightarrow 22.4 \text{ L at STP}$ $68 \text{ g}$ $\Rightarrow 22.4 \text{ L of oxygen produced from 68g H}_2\text{O}_2$ $10\text{L of O}_2 \text{ at STP is produced from } \frac{22.4 \times 68 \times 10\text{g}}{22.4} = 30.36 \text{ g}$ $\approx 30 \text{g H}_2\text{O}$ $\text{The strength of 10 Volume H}_2\text{O}_2 = 30 \text{ g/L}$ $3\% \text{ H}_2\text{O}_2 \text{ solution}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}