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Current Question (ID: 8713)

Question:
$\text{Hydrogen is placed separately in the periodic table because :}$
Options:
  • 1. $\text{It resembles alkali metals.}$
  • 2. $\text{It shows the same reactions as halogens.}$
  • 3. $\text{Both (1) and (2)}$
  • 4. $\text{None of the above.}$
Solution:
\text{HINT: Hydrogen resembles both alkali metals and halogens.} \text{Explanation:} \text{The resemblance with alkali metals:} \text{1. Like alkali metals, hydrogen contains one valence electron in its valency shell.} \text{Hence, it can lose one electron to form a unipositive ion.} \text{2. Like alkali metals, hydrogen combines with electronegative elements to} \text{form oxides, halides, and sulphides.} \text{The resemblance with halogens:} \text{1. Both hydrogen and halogens require one electron to complete their octets.} \text{Hence, hydrogen can gain one electron to form a uni-negative ion.} \text{2. Like halogens, it forms a diatomic molecule and several covalent compounds.} \text{Though hydrogen shows some similarity with both alkali metals and halogens,} \text{it differs from them on some grounds.} \text{Unlike alkali metals, hydrogen does not possess metallic characteristics.} \text{On the other hand, it possesses a high ionization enthalpy.} \text{Also, it is less reactive than halogens.} \text{Owing to these reasons, hydrogen cannot be placed with alkali metals} \text{(group I) or with halogens (group VII).} \text{In addition, it was also established that } \text{H}^{+} \text{ ions cannot exist freely} \text{as they are extremely small. } \text{H}^{+} \text{ ions are always associated with} \text{other atoms or molecules.} \text{Hence, hydrogen is best placed separately in the periodic table.}

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}