Import Question JSON

Current Question (ID: 8740)

Question:
$\text{Given below are two statements:}$ $\text{Assertion (A): When we change the unit of measurement of a quantity, its numerical value changes.}$ $\text{Reason (R): Smaller the unit of measurement, smaller is its numerical value.}$
Options:
  • 1. $\text{Both (A) and (R) are True and (R) is the correct explanation of (A).}$
  • 2. $\text{Both (A) and (R) are True but (R) is not the correct explanation of (A).}$
  • 3. $\text{(A) is True but (R) is False.}$
  • 4. $\text{Both (A) and (R) are False.}$
Solution:
$\text{Let us analyze both statements:}$ $\text{Assertion (A): When we change the unit of measurement of a quantity, its numerical value changes.}$ $\text{This statement is TRUE. For example, } 1 \text{ meter} = 100 \text{ centimeters. The physical quantity remains the same, but the numerical value changes from } 1 \text{ to } 100 \text{ when we change units from meters to centimeters.}$ $\text{Reason (R): Smaller the unit of measurement, smaller is its numerical value.}$ $\text{This statement is FALSE. When we use a smaller unit of measurement, we actually need MORE of those smaller units to represent the same physical quantity, so the numerical value becomes LARGER.}$ $\text{For example: } 1 \text{ meter} = 100 \text{ centimeters}$ $\text{Here, centimeter is a smaller unit than meter, but the numerical value (100) is larger than the original value (1).}$ $\text{Therefore, Assertion (A) is True but Reason (R) is False.}$ $\text{Hence, option (3) is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}