Import Question JSON

Current Question (ID: 8783)

Question:

$\text{Given below are two statements:}$ $\text{Statement A: In a number less than 1, all zeros on the right of decimal point are significant.}$ $\text{Statement B: Zeros between two non-zero numbers are not significant.}$

Options:

1. $\text{Statement A is correct.}$
2. $\text{Statement B is correct.}$
3. $\text{Both Statements A and Statement B are correct.}$
4. $\text{Both Statements A and Statement B are incorrect.}$

Solution:

$\text{Hint: Recall the rule of significant figures.}$ $\text{Explanation:}$ $\text{Statement A is incorrect. In a number less than 1, zeros immediately after the decimal point (leading zeros) are NOT significant as they only serve as placeholders. For example, in 0.0025, only the digits 2 and 5 are significant. However, trailing zeros after significant digits ARE significant.}$ $\text{Statement B is incorrect. Zeros between two non-zero numbers (captive zeros) ARE always significant. For example, in 1005, all four digits including the two zeros are significant.}$ $\text{Since both statements are incorrect, the correct answer is option 4.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}