Import Question JSON

Current Question (ID: 8793)

Question:

$\text{Find the thickness of the wire. The least count is 0.01 mm. The main scale reads: (in mm)}$ $\text{The diagrams show a measuring instrument in two positions - one without the wire and one with the wire placed between the jaws.}$

Options:

1. $7.62$
2. $7.63$
3. $7.64$
4. $7.65$

Solution:

$\text{From 1st figure,}$ $\text{Zero error} = 0.01 \text{ mm} \times 3 = 0.03 \text{ mm}$ $\text{From 2nd figure,}$ $\text{Observed Reading} = 7 \text{ mm} + 0.01\text{mm} \times 67$ $= 7.67 \text{ mm}$ $\text{Correct reading} = 7.67 \text{ mm} - 0.03 \text{ mm}$ $= 7.64 \text{ mm}$ $\text{Therefore, the main scale reading is 7.64 mm.}$ $\text{Hence, option (3) is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}