Import Question JSON

Current Question (ID: 8815)

Question:

$\text{A passenger arriving in a new town wishes to go from the station to a hotel located } 10 \text{ km away on a straight road from the station. A dishonest cabman takes him along a circuitous path } 23 \text{ km long and reaches the hotel in } 28 \text{ min. The average speed of the taxi is:}$

Options:

1. $30 \text{ km/h}$
2. $49.3 \text{ km/h}$
3. $55.6 \text{ km/h}$
4. $60 \text{ km/h}$

Solution:

\text{Hint: The average speed is defined as the total distance covered per unit time.} \text{Step 1: Convert the time into hours.} \text{Total time taken} = 28 \text{ min} = \frac{28}{60} \text{ hr} \text{Step 2: Find out the average speed.} \text{The average speed of the taxi} = \frac{\text{Total distance travelled}}{\text{Total time taken}} = \frac{23}{\frac{28}{60}} \text{Hence Option (2) is the correct answer.}

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}