Import Question JSON

Current Question (ID: 8904)

Question:

$\text{A lift is going up. The variation in the speed of the lift is as given in the graph. What is the height to which the lift takes the passengers?}$

Options:

1. $3.6 \text{ m}$
2. $28.8 \text{ m}$
3. $36.0 \text{ m}$
4. $\text{It cannot be calculated from the above graph.}$

Solution:

\text{Hint: Height = Area under the graph.} \text{Step: Find the height up to which the lift takes the passengers.} \text{The area of the trapezium is given by:} \text{Area} = \frac{1}{2} \times \text{sum of parallel sides} \times \text{height} \text{Area} = \text{Height} = \frac{1}{2} \times (8 + 12) \times 3.6 = 36 \text{ m} \text{Hence, option (3) is the correct answer.}

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}