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Current Question (ID: 9101)

Question:

$\text{The property of alkali metals that increases with increasing atomic number is -}$

Options:

1. $\text{First ionization energy.}$
2. $\text{Electronegativity.}$
3. $\text{Hydration energy of the univalent ion.}$
4. $\text{Atomic radius.}$

Solution:

$\text{HINT: Down the group size of atom increases.}$ $\text{Explanation:}$ $\text{1.) In general, the atomic radius increases in a group over time.}$ $\text{The number of energy levels (n) increases in a group downwards, since there is a larger distance between the nucleus and the outermost orbital.}$ $\text{This results in an increase in atomic radius.}$ $\text{2.) With the increase in atomic radii down the group, ionisation energy decreases.}$ $\text{3.) As the metal atoms increase in size, any bonding electron pair becomes farther from the metal nucleus, and so is less strongly attracted towards it.}$ $\text{This corresponds with a decrease in electronegativity down the group.}$ $\text{4.) Hydration depend on the charge/size ratio. The higher the ratio more will be the hydration of ion.}$ $\text{Thus, the degree of hydration of univalent ions decreases down the group.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}