Import Question JSON

Current Question (ID: 9107)

Question:

$\text{The reason for a lower basicity of hydroxides of alkaline earth metals than alkali metals is :}$

Options:

1. $\text{Alkali metals form ionic compounds.}$
2. $\text{The bond strength of oxygen is more for alkali metals.}$
3. $\text{The electropositivity of alkali metals is more than alkaline earth metals.}$
4. $\text{The electropositivity of alkali metals is less than alkaline earth metals.}$

Solution:

$\text{HINT: Alkali metals are more electropositive than alkaline earth metals.}$ $\text{Explanation:}$ $\text{The hydroxides of alkaline Earth metals are more ionic than the hydroxides of alkali metals.}$ $\text{It is because the hydroxide of alkaline Earth metals have greater lattice enthalpy than hydroxides of alkali metals which make the hydroxides of alkali metals less ionic than hydroxides of alkaline Earth metals.}$ $\text{As hydroxides of alkali metals are less ionic so it'd be easier for such compounds to dissociate in water than hydroxides of alkaline Earth metals.}$ $\text{Since, hydroxide of alkali metals metals can dissociate more easily into cation and hydroxide ion makes these compounds more basic.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}