Import Question JSON

Current Question (ID: 9120)

Question:

$\text{The incorrect statement among the following is-}$

Options:

1. $\text{Ionisation enthalpy of alkaline earth metals is higher than alkali metals.}$
2. $\text{Alkaline earth metal oxides are more basic than alkali metal oxides.}$
3. $\text{Alkaline earth metal hydroxides are less basic and less stable than alkali metal hydroxides.}$
4. $\text{Solubility of Alkaline earth metals and alkali metal hydroxide increases down the group.}$

Solution:

$\text{HINT: Left to right across the period basic character of oxide decreases.}$ $\text{Explanation:}$ $\text{1) The ionization enthalpy of alkaline earth metals is higher than alkali metals because of the increase in the nuclear charge of the alkaline earth metal.}$ $\text{2) Alkaline earth metals hydroxide is less basic and less stable than alkali metal hydroxides because left to right across the period basicity of hydroxide decreases.}$ $\text{3) Solubility of Alkaline earth metals and alkali metal hydroxide increases down the group because down the group ionic character increases. Hence, solubility increases.}$ $\text{4) The second statement is wrong, that is, alkaline earth metal oxides are more basic than alkali metal oxides. Left to right across the period basicity of oxide decreases because the covalent character increases.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}