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Current Question (ID: 9122)

Question:
$\text{All group-2 metals dissolve in liquid ammonia to produce a bright blue colour. The colour is due to-}$
Options:
  • 1. $\text{A change in the structure of ammonia.}$
  • 2. $\text{d-d transition.}$
  • 3. $\text{The spectrum of the solvated electrons.}$
  • 4. $\text{An electronic transition from a lower to a higher energy state.}$
Solution:
$\text{HINT: Solvated electron gives blue colour.}$ $\text{Explanation:}$ $\text{Step 1:}$ $\text{Like alkali metal, all alkaline earth metals dissolve in liquid ammonia.}$ $\text{The dilute solutions are bright blue in color due to solvated electrons.}$ $\text{The blue colour of the solution is due to the ammoniated electron which absorbs energy in the visible region of light and thus imparts blue colour to the solution.}$ $\text{Step 2:}$ $\text{The reaction is as follows:}$ $\text{M} + (x + y) \text{NH}_3 \rightarrow [\text{M}(\text{NH}_3)_x]^{1+} + [\text{e}(\text{NH}_3)_y]^{1-}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}