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Current Question (ID: 9124)

Question:
$\text{Alkali metals are characterised by:}$
Options:
  • 1. $\text{Good conductors of heat and electricity.}$
  • 2. $\text{High melting points.}$
  • 3. $\text{Low oxidation potentials.}$
  • 4. $\text{High ionisation potentials.}$
Solution:
$\text{HINT: Alkali metals are good conductors of heat and electricity.}$ $\text{Explanation:}$ $\text{1. All metals show metallic bonding involving oscillations of electrons in them and thus, are good conductor of heat and electricity.}$ $\text{2. Due to the large size of the alkali metals, and increase in shielding effect on increase in size of the alkali metals, it becomes easy to remove the outermost electron hence resulting in low ionization energy.}$ $\text{3. All Group 1 elements have one electron in their outermost shell which is held very weakly by the nucleus. The increasing atomic radius means weaker forces between the atoms and so a lower melting and boiling point.}$ $\text{4. The general outer electronic configuration of alkali metals is ns}^1\text{. They readily lose one valence shell electron to achieve stable noble gas configuration and hence, they are highly electropositive and are good reducing agents.}$ $\text{Hence, standard reduction potentials of alkali metals have high negative values i.e alkali metals have high oxidation potentials.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}