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Current Question (ID: 9126)

Question:
$\text{The strongest reducing agent among the following is:}$
Options:
  • 1. $\text{K}$
  • 2. $\text{Na}$
  • 3. $\text{Al}$
  • 4. $\text{Mg}$
Solution:
$\text{HINT: Alkali metals are the strongest reducing agents.}$ $\text{Explanation:}$ $\text{The ability of a substance to gain electrons is known as reduction potential.}$ $\text{Reducing power of alkali metals increases down the group.}$ $\text{Most of the elements have a certain value of reduction potential. For the given elements, the value of reduction potential will be as follows.}$ $\text{Na} = -2.71 \text{ V, Mg} = -2.38 \text{ V, Al} = -1.66 \text{ V, and K} = -2.92 \text{ V.}$ $\text{The higher the value of electrode potential lower will be reducing power of an element.}$ $\text{Hence, we can conclude that out of the given options K is the strongest reducing agent.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}