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Current Question (ID: 9134)

Question:

$\text{The correct order of thermal stability of carbonates of Group 2 elements is-}$

Options:

1. $\text{BeCO}_3 < \text{MgCO}_3 < \text{CaCO}_3 < \text{SrCO}_3 < \text{BaCO}_3$
2. $\text{BeCO}_3 < \text{MgCO}_3 < \text{BaCO}_3 < \text{SrCO}_3 < \text{CaCO}_3$
3. $\text{BaCO}_3 < \text{MgCO}_3 < \text{CaCO}_3 < \text{SrCO}_3 < \text{BeCO}_3$
4. $\text{BaCO}_3 < \text{CaCO}_3 < \text{MgCO}_3 < \text{SrCO}_3 < \text{BeCO}_3$

Solution:

$\text{HINT: The stability of carbonates increases down the group.}$ $\text{Explanation:}$ $\text{All the alkaline earth metals form carbonates (MCO}_3\text{). All these carbonates decompose on heating to give CO}_2 \text{ and metal oxide.}$ $\text{The thermal stability of these carbonates increases down the group, i.e., from Be to Ba, BeCO}_3 < \text{MgCO}_3 < \text{CaCO}_3 < \text{SrCO}_3 < \text{BaCO}_3\text{. BeCO}_3 \text{ is unstable to the extent that it is stable only in an atmosphere of CO}_2\text{.}$ $\text{It however shows reversible decomposition in closed container BeCO}_3 \rightleftharpoons \text{BeO} + \text{CO}_2$ $\text{Hence, more is the stability of oxide formed, less will be the stability of carbonates. The stability of oxides decreases down the group. Since beryllium oxide is highly stable, it makes BeCO}_3 \text{ unstable.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}