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Current Question (ID: 9138)

Question:

$\text{Solubility of alkaline earth metal sulphates in water decreases in the sequence:}$

Options:

1. $\text{Mg} > \text{Ca} > \text{Sr} > \text{Ba}$
2. $\text{Ca} > \text{Sr} > \text{Ba} > \text{Mg}$
3. $\text{Sr} > \text{Ca} > \text{Mg} > \text{Ba}$
4. $\text{Ba} > \text{Mg} > \text{Sr} > \text{Ca}$

Solution:

$\text{HINT: Solubility of sulfates of alkaline earth metals decreases down the group.}$ $\text{Explanation:}$ $\text{Solubility} \propto \text{Hydration energy} \propto \frac{1}{\text{lattice energy}}$ $\text{From top to bottom both hydration energy and lattice decrease down the group but the hydration energy decreases more rapidly than lattice energy.}$ $\text{Smaller cations form soluble salt with smaller anions and vice versa. Thus, on moving from BeSO}_4 \text{ to BaSO}_4 \text{ the solubility decreases.}$ $\text{That is why BaSO}_4 \text{ is insoluble in water and BeSO}_4 \text{ is soluble in water because of the small size Be}^{2+} \text{ ion.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}