Import Question JSON

Current Question (ID: 9152)

Question:

$\text{The incorrect statement among the following is -}$

Options:

1. $\text{The thermal stability of nitrates of groups 1 and 2 increases down the group.}$
2. $\text{Nitrates of both groups 1 and 2 are insoluble in water.}$
3. $\text{The solubility of alkali metal carbonates increases down the group.}$
4. $\text{The solubility of alkaline earth metals sulphates decreases down the group.}$

Solution:

$\text{Hint: Solubility depends on lattice energy, hydration energy, and different other factors.}$ $\text{Explanation:}$ $\text{STEP 1:}$ $\text{Alkali metal nitrates, carbonates, and sulfates have water solubility.}$ $\text{When you move down the group of alkali metals, you will observe that the solubility of alkali metal nitrates, carbonates, and sulfates increases.}$ $\text{This is due to a more rapid decrease in the lattice energies when compared to the hydration energies.}$ $\text{STEP 2:}$ $\text{As we move down group 1 and group 2, the thermal stability of nitrate increases. Nitrates of both group 1 and group 2 metals are soluble in water.}$ $\text{The solubility of K}_2\text{SO}_4 \text{ in water is-- 16g at 50°C.}$ $\text{The solubility of Rb}_2\text{SO}_4 \text{ in water is -- 50.8 (g/L)at 50 degree}$ $\text{The solubility of Rb}_2\text{SO}_4 \text{ in water is --179 g/100 ml (20 °C)}$ $\text{Therefore, statement 2 is incorrect as nitrates of both groups are actually soluble in water, not insoluble.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}