Import Question JSON

Current Question (ID: 9153)

Question:
$\text{Out of Be, Mg, Ca, Sr and Ba,}$ $\text{Total number of metal whose nitrates are decomposed according to the following reaction are:}$ $2\text{M(NO}_3\text{)}_2 \xrightarrow{\Delta} \text{Residue} + 4\text{NO}_2 + \text{O}_2$
Options:
  • 1. $5$
  • 2. $4$
  • 3. $3$
  • 4. $2$
Solution:
$\text{HINT: All group 2 elements nitrates decomposes.}$ $\text{Explanation:}$ $\text{The Group 2 nitrates undergo thermal decomposition to the metal oxide, nitrogen dioxide and oxygen gas.}$ $\text{These compounds are white solids and brown nitrogen dioxide and oxygen gases are also given off when heated.}$ $\text{Both carbonates and nitrates of Group 2 elements become more thermally stable down the group.}$ $\text{The larger compounds further down require more heat than the lighter compounds in order to decompose.}$ $\text{All the given elements Be, Mg, Ca, Sr and Ba are Group 2 elements, so all their nitrates decompose according to the given reaction pattern:}$ $2\text{M(NO}_3\text{)}_2 \xrightarrow{\Delta} 2\text{MO (Residue)} + 4\text{NO}_2 + \text{O}_2$ $\text{Therefore, all 5 metals have nitrates that decompose according to this reaction.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}