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Current Question (ID: 9157)

Question:

$\text{In the Solvay process of manufacturing sodium carbonate, the raw materials used are:}$

Options:

1. $\text{Aqueous NaOH, NH}_3 \text{ and CO}_2$
2. $\text{Molten NaOH, NH}_3 \text{ and CO}$
3. $\text{Brine NaCl, NH}_3 \text{ and CO}$
4. $\text{Brine NaCl, NH}_3 \text{ and CO}_2$

Solution:

$\text{HINT: Brine NaCl, NH}_3 \text{ and CO}_2 \text{ are raw materials in Solvay's process.}$ $\text{Explanation:}$ $\text{The Solvay process is an industrial process that uses limestone (CaCO}_3\text{) to produce carbon dioxide (CO}_2\text{) which reacts with ammonia (NH}_3\text{) dissolved in brine (concentrated NaCl(aq)) to produce sodium carbonate.}$ $\text{The chemical reactions involved in the Solvay process are as below:}$ $\text{NH}_3 + \text{CO}_2 + \text{H}_2\text{O} \rightarrow \text{NH}_4\text{HCO}_3$ $\text{NH}_4\text{HCO}_3 + \text{NaCl} \xrightarrow{30°\text{C}} \text{NaHCO}_3 \downarrow + \text{NH}_4\text{Cl}$ $2\text{NaHCO}_3 \text{ again used} \xrightarrow{250°\text{C}} \text{Na}_2\text{CO}_3 + \text{H}_2\text{O} + \text{CO}_2$ $2\text{NH}_4\text{Cl again used} + \text{Ca(OH)}_2 \rightarrow \text{CaCl}_2 \text{ lime slaked} + 2\text{H}_2\text{O} + 2\text{NH}_3$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}