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Current Question (ID: 9158)

Question:
$(\text{NH}_4)_2 \text{Cr}_2 \text{O}_7 \text{ on heating (below 200 degrees celsius) liberates a gas. The same gas will be obtained below 600 degrees celsius by :}$
Options:
  • 1. $\text{Heating }\text{NH}_4 \text{NO}_2$
  • 2. $\text{Heating }\text{NH}_4 \text{NO}_3$
  • 3. $\text{Heating }\text{Mg}_3 \text{N}_2$
  • 4. $\text{None of the above}$
Solution:
$\text{Hint: }(\text{NH}_4)_2 \text{Cr}_2 \text{O}_7 \text{ gives nitrogen gas.}$ $\text{Explanation:}$ $\text{Upon heating, ammonium compound decomposes to give-}$ $\text{NH}_4\text{NO}_3 \rightarrow \text{N}_2\text{O} + 2\text{H}_2\text{O}$ $\text{NH}_4\text{NO}_2 \rightarrow \text{N}_2 + 2\text{H}_2\text{O}$ $\text{Magnesium nitride decomposes at }800^\circ\text{C temperature to give nitrogen, but in question, the temp limit is 600.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}