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Current Question (ID: 9168)

Question:

$\text{The incorrect statement among the following is -}$

Options:

1. $\text{Li}^+ \text{ has minimum degree of hydration among alkali metal cations.}$
2. $\text{The oxidation state of K in } \text{KO}_2 \text{ is } +1$
3. $\text{Sodium is used to make Na / Pb alloy.}$
4. $\text{MgSO}_4 \text{ is readily soluble in water.}$

Solution:

$\text{HINT: Degree of hydration } \propto \frac{\text{Charge}}{\text{Size}}$ $\text{Explanation:}$ $\text{1. For the elements having same charge, as the size of ion increases degree of hydration will decreases.}$ $\text{On moving down the group the size of alkali metal is increasing, so, degree of hydration will decrease down the group.}$ $\text{Li}^+ \text{ has maximum degree of hydration among alkali metal cations.}$ $\text{Order of hydration: } \text{Li}^+ > \text{Na}^+ > \text{K}^+ > \text{Rb}^+ > \text{Cs}^+$ $\text{2. } \text{KO}_2 \text{ is a superoxide. Oxidation state of K = x + 2(-1/2) = 0}$ $\text{So, oxidation state of potassium is } +1$ $\text{3. Sodium-lead alloy is used as a dessicant, a reducing agent, and a precursory material for the synthesis of tetraethyllead.}$ $\text{4. } \text{Mg}^{2+} \text{ being smaller in size, thus hydration energy predominates over lattice energy of } \text{MgSO}_4\text{. Thus, } \text{MgSO}_4 \text{ is soluble in water.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}