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Current Question (ID: 9176)

Question:

$\text{LiF is almost insoluble in water whereas LiCl is soluble in water and acetone both, because of:}$

Options:

1. $\text{Greater covalent character of LiCl as compared to LiF.}$
2. $\text{Greater hydration energy of LiF as compared to LiCl.}$
3. $\text{Greater size of LiF as compared to LiCl.}$
4. $\text{Greater lattice energy of LiF as compared to LiCl.}$

Solution:

$\text{HINT: LiF has more ionic character than LiCl.}$ $\text{Explanation:}$ $\text{STEP 1:}$ $\text{In the case of LiF due to the small size of fluoride, it forms a strong bond with lithium. As a result, it shows high lattice enthalpy but lower hydration enthalpy. Due to this LiF is insoluble in water.}$ $\text{On the other hand, due to the large size of the chlorine atom, the bond is weaker with lithium as a result it shows lower lattice energy. Due to this, it is soluble in water.}$ $\text{STEP 2:}$ $\text{And also, LiCl shows partial covalent in nature due to the large size of a chlorine atom. So, for this covalent nature, it is also soluble in acetone.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}