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Current Question (ID: 9177)

Question:

$\text{HCl was passed through a solution of } \text{CaCl}_2, \text{MgCl}_2, \text{ and NaCl. Compound(s) that get crystallize is/are-}$

Options:

1. $\text{Only NaCl}$
2. $\text{Only } \text{MgCl}_2$
3. $\text{NaCl, } \text{MgCl}_2, \text{ and } \text{CaCl}_2$
4. $\text{Both } \text{MgCl}_2 \text{ and } \text{CaCl}_2$

Solution:

$\text{HINT: Hydration depends on the charge/size ratio.}$ $\text{Explanation:}$ $\text{In the case of } \text{MgCl}_2 \text{ and } \text{CaCl}_2, \text{ due to the high charge/size ratio, they form hydrated salt in place of getting crystallizes.}$ $\text{When HCl is passed through the mixture } \text{Cl}^- \text{ ion concentration increases. Hence ionic product } [\text{Na}^+][\text{Cl}^-] \text{ becomes more than solubility product. So NaCl will precipitate out.}$ $\text{Calcium and magnesium chloride being more soluble than NaCl remain in the solution.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}