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Current Question (ID: 9197)

Question:
$\text{Calcium hydroxide upon reacting with moist chlorine forms-}$
Options:
  • 1. $\text{CaCl}_2$
  • 2. $\text{Ca}(\text{OCl})_2$
  • 3. $\text{CaCl}_2 \cdot 2\text{H}_2\text{O}$
  • 4. $\text{CaCl}_2 \cdot 7\text{H}_2\text{O}$
Solution:
$\text{Hint: Bleaching powder is formed.}$ $\text{Explanation:}$ $\text{Chlorine reacts with freshly prepared calcium hydroxide to produce bleaching powder.}$ $2\text{Ca}(\text{OH})_2 + 2\text{Cl}_2 \rightarrow \text{CaCl}_2 + \text{Ca}(\text{OCl})_2 + 2\text{H}_2\text{O} \text{ (bleaching powder)}$ $\text{Calcium hydroxide is an odourless white powder.}$ $\text{It's used in industrial settings, such as sewage treatment, paper production, construction, and food processing.}$ $\text{Calcium hypochlorite is an inorganic compound with the formula Ca(OCl)}_2\text{.}$ $\text{It is the main active ingredient of commercial products called bleaching powder, chlorine powder, or chlorinated lime, used for water treatment and as a bleaching agent.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}