Import Question JSON

Current Question (ID: 9199)

Question:

$\text{The suspension of slaked lime in water is known as -}$

Options:

1. $\text{Limewater.}$
2. $\text{Quicklime.}$
3. $\text{Milk of lime.}$
4. $\text{Aqueous solution of slaked lime.}$

Solution:

$\text{Hint: Milk of lime}$ $\text{Explanation:}$ $\text{Aqueous solution of slaked lime is called lime water whereas suspension solution of slaked lime is called milk of lime.}$ $\text{Limewater is an alkaline solution made from calcium hydroxide that is sparingly soluble in water, water reacts with calcium oxide to produce this substance.}$ $\text{When lime is combined with water, only a small portion of it dissolves, forming limewater, while the remainder remains as a suspension known as milk of lime.}$ $\text{Milk of lime is used in the sugar industry for pH correction and as auxiliary of flocculation in bleaching of the sugar solution.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}