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Current Question (ID: 9204)

Question:

$\text{An oxide that does not react with sodium hydroxide is:}$

Options:

1. $\text{B}_2\text{O}_3$
2. $\text{CaO}$
3. $\text{SiO}_2$
4. $\text{BeO}$

Solution:

$\text{HINT: Basic oxide does not react with the base.}$ $\text{Explanation: It is a fact that acid reacts with a base and a base reacts with an acid.}$ $\text{So here, the oxide which will be most acidic will react with the base i.e. sodium hydroxide.}$ $\text{Now, as BeO is amphoteric oxides, SiO}_2 \text{ and B}_2\text{O}_3 \text{ are acidic oxides and CaO is a basic oxide.}$ $\text{So, the basic oxide CaO is not expected to react with NaOH.}$ $\text{The reactions of oxides with NaOH are as follows:}$ $\text{1. BeO + 2NaOH + H}_2\text{O} \rightarrow \text{Na}_2[\text{Be(OH)}_4]$ $\text{2. B}_2\text{O}_3 + 2\text{NaOH} \rightarrow 2\text{NaBO}_2 + \text{H}_2\text{O}$ $\text{3. SiO}_2 + 2\text{NaOH} \rightarrow \text{Na}_2\text{SiO}_3 + 2\text{H}_2\text{O}$ $\text{4. CaO + NaOH} \rightarrow \text{No reaction}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}