Import Question JSON

Current Question (ID: 9213)

Question:

$\text{The incorrect statement among the following is-}$

Options:

1. $\text{The milk of magnesia used as an antacid is chemically MgO + MgCl}_2$
2. $\text{Stability of alkali metal peroxides increases with an increase in atomic number.}$
3. $\text{Hydration energy of AgF is higher than its lattice energy.}$
4. $\text{Anhydrous MgCl}_2 \text{ cannot be prepared by direct heating of MgCl}_2 \cdot \text{6H}_2\text{O}$

Solution:

$\text{HINT: Milk of magnesia of MgO + H}_2\text{O}.$ $\text{Explanation:}$ $\text{1.) Milk of magnesia of MgO + H}_2\text{O not MgO + MgCl}_2\text{. It is a laxative (osmotic-type) that is thought to work by drawing water into the intestines, an effect that helps to cause movement of the intestines.}$ $\text{2.) The increasing stability of the peroxide or superoxide, as the size of the metal ion increases, is due to the stabilisation of large anions by larger cations through lattice energy effects.}$ $\text{3.) Hydration energy depends on the charge/size ratio. AgF has higher hydration energy than its lattice energy.}$ $\text{4.) Anhydrous MgCl}_2 \text{ is obtained by heating the hydrated salt with dry HCl.}$ $\text{Therefore, statement 1 is incorrect as milk of magnesia is MgO + H}_2\text{O, not MgO + MgCl}_2\text{.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}