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Current Question (ID: 9214)

Question:

$\text{Nitrolim (a nitrogenous fertilizer) is a mixture of-}$

Options:

1. $\text{Calcium carbide and calcium cyanamide.}$
2. $\text{Calcium oxide and calcium carbide.}$
3. $\text{Calcium cyanamide and carbon.}$
4. $\text{Calcium oxide and carbon.}$

Solution:

$\text{HINT: Nitrolim = CaCN}_2 + \text{C}$ $\text{Explanation:}$ $\text{A mixture of calcium cyanamide and carbon is nitrolim.}$ $\text{CaC}_2 + \text{N}_2 \xrightarrow{1000°\text{C}} \text{CaCN}_2 + \text{C}$ $\text{Cal. cyanamide (Nitrolim)}$ $\text{It is used as inorganic nitrogenous fertilizer. In common terms, it is also known as lime nitrogen.}$ $\text{It is a very effective fertiliser as by simply adding water to Nitrolim, the production of both Calcium Carbonate and Ammonia takes place, both of which are excellent fertilisers in their own right.}$ $\text{Ammonia (NH}_3\text{) is the foundation for the nitrogen (N) fertilizer industry.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}