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Current Question (ID: 9216)

Question:

$\text{The incorrect equation for Solvay process is -}$

Options:

1. $\text{Ca(OH)}_2 + 2\text{NH}_4\text{Cl} \rightarrow \text{NH}_3 + 2\text{H}_2\text{O} + \text{CaCl}_2$
2. $2\text{NaHCO}_3 \rightarrow \text{Na}_2\text{CO}_3 + \text{CO}_2 + \text{H}_2\text{O}$
3. $2\text{NaCl} + \text{CaCO}_3 \rightarrow \text{Na}_2\text{CO}_3 + \text{CaCl}_2$
4. $\text{None of the above.}$

Solution:

$\text{HINT: Solvay process is used to prepare sodium carbonate.}$ $\text{Explanation:}$ $\text{When carbon dioxide gas is bubbled through a brine solution saturated with ammonia, sodium hydrogen carbonate is formed. This sodium hydrogen carbonate is then converted to sodium carbonate.}$ $\text{Step 1: Brine solution is saturated with ammonia.}$ $2\text{NH}_3 + \text{H}_2\text{O} + \text{CO}_2 \rightarrow (\text{NH}_4)_2\text{CO}_3$ $\text{This ammoniated brine is filtered to remove any impurity.}$ $\text{Step 2: Carbon dioxide is reacted with this ammoniated brine to result in the formation of insoluble sodium hydrogen carbonate.}$ $\text{NH}_3 + \text{H}_2\text{O} + \text{CO}_2 \rightarrow \text{NH}_4\text{HCO}_3$ $\text{NaCl} + \text{NH}_4\text{HCO}_3 \rightarrow \text{NaHCO}_3 \downarrow + \text{NH}_4\text{Cl}$ $\text{Step 3: The solution containing crystals of } \text{NaHCO}_3 \text{ is filtered to obtain } \text{NaHCO}_3.$ $\text{Step 4: } \text{NaHCO}_3 \text{ is heated strongly to convert it into } \text{Na}_2\text{CO}_3.$ $2\text{NaHCO}_3 \rightarrow \text{Na}_2\text{CO}_3 + \text{CO}_2 + \text{H}_2\text{O}$ $\text{Step 5: To recover ammonia, the filtrate (after removing } \text{NaHCO}_3\text{) is mixed with } \text{Ca(OH)}_2 \text{ and heated.}$ $\text{Ca(OH)}_2 + 2\text{NH}_4\text{Cl} \rightarrow 2\text{NH}_3 + 2\text{H}_2\text{O} + \text{CaCl}_2$ $\text{The overall reaction taking place in the Solvay process is}$ $2\text{NaCl} + \text{CaCO}_3 \rightarrow \text{Na}_2\text{CO}_3 + \text{CaCl}_2$ $\text{CO}_2 \text{ is prepared by decomposition of } \text{CaCO}_3$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}