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Current Question (ID: 9220)

Question:
$\text{Sodium hydroxide can be prepared by:}$
Options:
  • 1. $\text{Down's Process.}$
  • 2. $\text{Castner-Kellner process.}$
  • 3. $\text{Solvay's Process.}$
  • 4. $\text{None of the above.}$
Solution:
$\text{HINT: Down's process is used for the preparation of Na metal.}$ $\text{Explanation:}$ $\text{STEP 1:}$ $\text{Sodium can be extracted from sodium chloride by the Down's process. This process involves the electrolysis of fused } \text{NaCl} \text{ (40\%) and } \text{CaCl}_2 \text{ (60\%) at a temperature of 1123 K in Down's cell. Steel is the cathode and a block of graphite acts as the anode. Metallic Na and Ca are formed at the cathode. Molten sodium is taken out of the cell and collected over kerosene.}$ $\text{STEP 2:}$ $\text{Sodium hydroxide can be prepared by the electrolysis of sodium chloride. This is called Castner-Kellner process. In this process, the brine solution is electrolyzed using a carbon anode and a mercury cathode.}$ $\text{STEP 3:}$ $\text{Sodium carbonate is prepared by the Solvay process.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}