Import Question JSON

Current Question (ID: 9589)

Question:
$\text{The speed of water in a river is 4 km/h and a man can swim at 5 km/h. The minimum time taken by the man to cross the river of width 200 m is:}$
Options:
  • 1. $\frac{1}{5}\text{ h}$
  • 2. $\frac{1}{25}\text{ h}$
  • 3. $\frac{1}{15}\text{ h}$
  • 4. $\frac{1}{20}\text{ h}$
Solution:
\text{Hint: } \vec{v}_{MR} \text{ should be } \perp \text{ to } \vec{v}_{RG} \text{Step 1: Identify condition of minimum time} \text{For minimum time to cross the river, the man should swim perpendicular to the river flow. The component of man's velocity perpendicular to the river should be maximum.} \text{From the vector diagram, the effective velocity perpendicular to the river is the full swimming velocity of the man, which is 5 km/h.} \text{Width of river = 200 m = 0.2 km} t = \frac{\text{distance}}{\text{velocity}} = \frac{0.2}{5} = \frac{1}{25}\text{ h}

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}