Import Question JSON

Current Question (ID: 9692)

Question:
$\text{A man sitting in a bus travelling in a direction from west to east with a speed of 40 km/h observes that the rain-drops are falling vertically downwards. To another man standing on ground the rain will appear:}$
Options:
  • 1. $\text{To fall vertically downwards}$
  • 2. $\text{To fall at an angle going from west to east}$
  • 3. $\text{To fall at an angle going from east to west}$
  • 4. $\text{The information given is insufficient to decide the direction of the rain}$
Solution:
$\text{A man is sitting in a bus and travelling from west to east, and the rain drops are appears falling vertically down.}$ $\text{Let us analyze this using relative motion:}$ $v_m = \text{velocity of man}$ $v_r = \text{Actual velocity of rain which is falling at an angle } \theta \text{ with vertical}$ $v_{rm} = \text{velocity of rain w.r.t. to moving man}$ $\text{From the vector diagram, we can see that the rain has components in both vertical and horizontal directions.}$ $\text{Since the man in the bus observes rain falling vertically, this means the horizontal component of rain's actual velocity equals the bus's velocity.}$ $\text{For a stationary observer on the ground, the rain will appear to fall at an angle because they can observe both the vertical and horizontal components of the rain's actual velocity.}$ $\text{Since the bus is moving from west to east, and the rain appears vertical to the moving observer, the actual rain must be falling at an angle going from west to east when observed from the ground.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}