Import Question JSON

Current Question (ID: 9719)

Question:
$\text{Two masses, } m_1 \text{ and } m_2 \text{ are experiencing the same force where } m_1 < m_2\text{. The ratio of their acceleration } \frac{a_1}{a_2} \text{ is:}$
Options:
  • 1. $1$
  • 2. $\text{less than 1}$
  • 3. $\text{greater than 1}$
  • 4. $\text{all the three cases}$
Solution:
\text{Hint: If the net force on two masses is the same then } a \propto \frac{1}{m} \text{Step 1: According to question:} F = m_1 a_1 = m_2 a_2 \text{Step 2: Use the above relation to find the required ratio.} \frac{a_1}{a_2} = \frac{m_2}{m_1} > 1 \quad \text{(As } m_1 < m_2\text{)}

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}