Import Question JSON

Current Question (ID: 9738)

Question:

$\text{If a young man of mass } 60 \text{ kg stands on the floor of a lift which is accelerating downwards at } 1 \text{ m/s}^2\text{, then the reaction of the floor of the lift on the man will be: } (g = 9.8 \text{ m/s}^2)$

Options:

1. $528 \text{ N}$
2. $540 \text{ N}$
3. $546 \text{ N}$
4. $\text{None of these}$

Solution:

$\text{Hint: Normal reaction, N = effective weight(W).}$ $\text{Step 1: Draw the FBD for the man.}$ $\text{The forces acting on the man are:}$ $\text{- Weight } mg \text{ (downward)}$ $\text{- Normal reaction } N \text{ (upward)}$ $\text{- Acceleration } a = 1 \text{ m/s}^2 \text{ (downward)}$ $\text{Step 2: Write the force equation.}$ $mg - N = ma$ $N = mg - ma = m(g - a)$ $N = 60 \times (9.8 - 1) = 60 \times 8.8 = 528 \text{ N}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}